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### Topic: Answer Verification : finding the volume occupied by 1.0 kg of CO...  (Read 3349 times)

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#### afchick7689

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##### Answer Verification : finding the volume occupied by 1.0 kg of CO...
« on: September 04, 2005, 02:23:34 PM »
Heres the problem, my work, and my answer--

if someone could please check over this, i think i must have made an error somewhere because the answer seems very large...

What would be the volume occupied by 1.0 kg of carbon monoxide at 700 °C and 0.1 atm?

PV= nRT

0.1 atm * V = n * 0.0821 * (700 + 273.15)
To find n --
1.0 kg CO  | 1000 g CO = 1000 g CO
| 1 kg CO
molar mass of CO = (12.01) + (16.00) = 28.01g
1000 g CO |   1 mol CO    =    35.702 mol CO
| 28.01 g CO
...SO:
0.1 atm * V = 35.702 mol CO*0.0821*(700 + 273.15)
.01 V = 2852.43
V= 285243.32 L (W/ SIG FIGS: 300000 L)

#### Yggdrasil

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##### Re:Answer Verification : finding the volume occupied by 1.0 kg of CO...
« Reply #1 on: September 04, 2005, 04:04:18 PM »
The second-to-last line should read:

0.1 V = 2852.43

Which is why your answer is off by a factor of 10.

#### afchick7689

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##### Re:Answer Verification : finding the volume occupied by 1.0 kg of CO...
« Reply #2 on: September 05, 2005, 10:02:48 AM »
thanks!