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Topic: Degree level exam question.. Can anyone answer this!? (Acids & bases)  (Read 2263 times)

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Offline Natalie_Noodle13

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At 298 K, the Ka for the dissociation of ethanoic acid in water is 1.8 x 10-5 mol dm-3 and the autoprotolysis constant (Kw) of water is 1.0 x 10-14 mol2 dm-6.  Calculate the basicity constant (Kb) of the ethanoate ion in water at 298 K.

I calculated it as;
Ka x Kb = Kw
Kb = Kw/Ka

= 1.0x10-14 / 1.8x10-5 = 5.55x10-10

Is this right?
Thanks :) x

Offline Borek

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Re: Degree level exam question.. Can anyone answer this!? (Acids & bases)
« Reply #1 on: January 11, 2011, 02:17:45 PM »
OK. You may have problems if you will have to deal with significant digits fanatic ;)
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