for part 2, though, the temperature given is 100 C, which only has 1 sig fig, which is why i left my answer with only one sig fig...
for part 3, i looked up the the specific heat of water and found it is 4.18 j/g C. So i think i know the equation that i need to use for the third part, is it mDTCp(cold) = -mDTCp(hot) ? --
so i would plug in the values, except the one thing im confused about would be the change in temperature that I should put on both sides??