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Topic: answer verification-- combustion of methane problem  (Read 3478 times)

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afchick7689

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answer verification-- combustion of methane problem
« on: September 05, 2005, 07:05:43 PM »
Can someone just check my work/answer please?

How many liters of oxygen would be required for the complete combustion of 1.0 gram of methane?  Assume STP.

O2 + CH4 –> CO2 + 4H
Molar Mass of CH4= (12.01) + (1.01 * 4)= 16.05 mol CH4
1.0 g CH4 |   1 mol CH4 = 0.0623 mol CH4
               | 16.05 g CH4  
0.0623 mol CH4 |  1 mol O2 = 0.0623 mol O2
                        | 1 mol CH4
PV=nRT
1atm * V = 0.0623mol O2 * (0.0821L/atm * mol/K) * 273.15 K
1V = 1.39712
V = 1.4 L O2

thanks so much!!

Offline xiankai

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Re:answer verification-- combustion of methane problem
« Reply #1 on: September 05, 2005, 08:48:50 PM »
good job :D
one learns best by teaching

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