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Topic: Write down the reaction between 1-pentyne and 2 molar HBr?  (Read 5458 times)

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Offline THISMOMENTISFATE

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Write down the reaction between 1-pentyne and 2 molar HBr?

http://img718.imageshack.us/i/triple2.jpg/
should there be 2 br or 4?

should i have drawn 2 brs attacking in the middle step? or should there be four steps?
« Last Edit: March 14, 2011, 10:01:28 PM by THISMOMENTISFATE »

Offline Nobby

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Re: Write down the reaction between 1-pentyne and 2 molar HBr?
« Reply #1 on: March 15, 2011, 02:17:12 AM »
First Reaction   R-CCH  + HBr  => R-CBr=CH2

Second Reaction: R-CBr=CH2 + HBr => R-CBr2-CH3

Law of Markownikov

Offline THISMOMENTISFATE

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Re: Write down the reaction between 1-pentyne and 2 molar HBr?
« Reply #2 on: March 15, 2011, 02:30:33 PM »
why R-CCH doesnt it have to be 1-pentyne??

Offline Nobby

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Re: Write down the reaction between 1-pentyne and 2 molar HBr?
« Reply #3 on: March 15, 2011, 03:30:59 PM »
1-Pentyne is CH3CH2CH2-CCH

With R = n-Propyl CH3CH2CH2- we got R-CCH

Ni zhidao?

Offline THISMOMENTISFATE

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Re: Write down the reaction between 1-pentyne and 2 molar HBr?
« Reply #4 on: March 15, 2011, 05:56:12 PM »
oh ok, our teacher hasnt taught us that yet, we stil write out all the ch's

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