[Auroturtle]

But... if you think about it that way 1 mol of CaCl₂ would also equal 1 mol of Na₂CO₃

Which doesn't make any sense.

[Borek]

Actually it makes sense, that's what stoichiometry is about. Same number of moles of CaCl₂ and Na₂CO₃ react giving same number of CaCO₃ and twice that number of moles of NaCl. If there is an excess of one of the reactants (be it CaCl₂ or Na₂CO₃) it won't react - it will be left in the mixture, as it has nothing it can react with.

[Auroturtle]

Dude this is so confusing 

I massed the precipitate (CaCO₃) yesterday and got 1.53g

Which = 0.0153 mol

So... does this mean that there are 0.0153 mol Na₂CO₃?

[Nobby]

Yes correct.

[Auroturtle]

Woot! Problem solved... lol that was incredibly easy, thanks everyone =D Mole snacks for all

[Auroturtle]

Nvm.