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Topic: volumetric problems  (Read 4639 times)

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Offline Supergirl00

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volumetric problems
« on: March 30, 2011, 05:52:13 AM »
Hi there,

How do you calculate this:
What volume of solution is needed to obtain 2moles NaCl from 0.1M NaCl solution ?

cant seem to get the answer   :'(.. thanks

Offline sjb

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Re: volumetric problems
« Reply #1 on: March 30, 2011, 06:08:26 AM »
Hi there,

How do you calculate this:
What volume of solution is needed to obtain 2moles NaCl from 0.1M NaCl solution ?

cant seem to get the answer   :'(.. thanks


What does it mean if a solution is 0.1M?

Offline LukeeeeBennett

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Re: volumetric problems
« Reply #2 on: March 30, 2011, 04:33:35 PM »
Number of moles of solution = Concentration x Volume

-REARRANGE-

Volume = Number of moles of solution ÷  Concentration

So,

Volume = 2 ÷ 0.1 = 20cm3 = 0.02dm3


Offline sjb

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Re: volumetric problems
« Reply #3 on: March 30, 2011, 05:05:49 PM »
Number of moles of solution = Concentration x Volume

-REARRANGE-

Volume = Number of moles of solution ÷  Concentration

Fine, but...

So,
Volume = 2 ÷ 0.1 = 20cm3 = 0.02dm3



this is not

Offline LukeeeeBennett

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Re: volumetric problems
« Reply #4 on: March 31, 2011, 12:58:23 PM »
Number of moles of solution = Concentration x Volume

-REARRANGE-

Volume = Number of moles of solution ÷  Concentration

Fine, but...

So,
Volume = 2 ÷ 0.1 = 20cm3 = 0.02dm3



this is not

Ooops, where did I go wrong? It was probably 20dm3 right? :(

Offline vmelkon

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Re: volumetric problems
« Reply #5 on: April 01, 2011, 09:29:27 AM »
20 cm3 is 0.02 dm3

Offline Nobby

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Re: volumetric problems
« Reply #6 on: April 01, 2011, 11:56:38 AM »
More easier: o,1 M = o,1 mol/l

So if you need 2 mol then you need 20 times of the Volumen. What means 20 l.

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