Given the following data:
2O3 → 3O2 ΔH = -430 kJ
O2 → 2O ΔH = +500 kJ
NO + O3 → NO2 + O2 ΔH = -203 kJ
Calculate ΔH for the reaction
NO + O → NO2
What I did first was I saw that they wanted O as a reactant instead of a product so I switched equation 2 around.
2O----->O2
we need O by itself so I divide by 2
O-------1/2O
I understand that we have to keep equation 3 the same. So I know im making a mistake in equation one.
I am dividing by 2
O3-------------->3/2O2
but the equation doesnt seem to be cancling out.
What exacly am I missing?