This depends on the other reaction conditions. What exact reaction are you interested in?
In the following article Cho,E.J.;Senecal, T. D. ;Kinzel,T.;Zhang,Y.;Watson,D.A.;Buchwald,S.L., Science ,2010, 328, 679.
They are doing trifluoromethylation of aryl halide so the starting material is aryl halide which in the presence of [(allyl)PdCl]2, brettphos or ruphos ligands (which are O and P donors) , TESCF3( source of trifluoromethyl anion ), KF and dioxan as solvent gives trifluoromethylated aromatic compound. In this reaction Pd goes from Pd(0) to Pd(II) but Pd in [(allyl)PdCl]2 is already in Pd(II) state.