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Topic: Color-Changing Reaction with KMnO4, table sugar, NaOH and H2O  (Read 7524 times)

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Offline khwaish

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Hi there,
I have a few questions about a theoretical experiment involving a color-changing reaction. One would add a KMnO4 solution to another solution of H2O, NaOH and C12H22O11.
I was looking at an article on crystal field theory and thought because of the permanganate's changing ionic structure and possibly different electron configuration and charge, that a color change would make sense from purple to blue to green to orange?
With each visible color change, does anyone know what the products would be, or the equation that would exhibit each change? (I thought it would look like: ions of MnO4-, reduced to blue MnO4-3, then to green MnO4-2, then yellow or orange?)
Or better yet, an explanation on why this happens?
Thank you so much!

Offline Nobby

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Re: Color-Changing Reaction with KMnO4, table sugar, NaOH and H2O
« Reply #1 on: April 07, 2011, 01:56:24 AM »
The reaction will go directly to MnO2 sludge.  I dont think with sugar it will be possible to get all the other oxidation step of manganese between.

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