[sugarwink]

I understand how to complete the first part of this question. The second part where the solute is volatile has confused me a bit. Help would be greatly appreciated. Thanks! =)

1) 5.821 g of a non-volatile solute is dissolved in 285.0 g of water.
    The solute does not react with water nor dissociate in solution.
    Assume that the resulting solution displays ideal Raoult's law behaviour.
    At 25°C the vapour pressure of the solution is 23.567 torr. 
    The vapour pressure of pure water at 25°C is 23.756 torr.
    Calculate the molar mass of the solute (g/mol).

2) Now suppose, instead, that 5.821 g of a volatile solute is dissolved in 285.0 g of water.
    This solute also does not react with water nor dissociate in solution.
    The pure solute displays, at 25°C, a vapour pressure of 2.376 torr.
    Again, assume an ideal solution.
    If, at 25°C the vapour pressure of this solution is also 23.567 torr.
    Calculate the molar mass of this volatile solute.