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Topic: Net ionic equation at 1st equivalence point for NaOH+H3PO4  (Read 14792 times)

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Offline BioMajor

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Net ionic equation at 1st equivalence point for NaOH+H3PO4
« on: April 11, 2011, 12:18:51 PM »
I did an experiment last week and need to write a net ionic equation for the titration of NaOH and H3PO4 at its first equivalence point. I am getting 3OH-(aq)+3H+<--->3H2O(l), but I know this isn't right? I'm not exactly sure what I'm doing wrong? My starting reaction that I have is 3NaOH(aq) + H3PO4(aq)<------> Na3PO4(aq) + 3H2O (l).

Thank you for any advice!

Offline tamim83

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Re: Net ionic equation at 1st equivalence point for NaOH+H3PO4
« Reply #1 on: April 11, 2011, 12:27:56 PM »
Phosphoric acid is a weak electrolyte so you cannot dissociate it into ions.

Hope that helps some. 

Offline BioMajor

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Re: Net ionic equation at 1st equivalence point for NaOH+H3PO4
« Reply #2 on: April 11, 2011, 12:42:52 PM »
Oh wow, now I feel stupid, lol. I don't know why I wasn't thinking about that. Lack of sleep may have something to do with it, lol.

I do have another question though. I have seen some people completing this reaction as I did, but some have it as NaOH (aq) + H3PO4(aq)----> NaH2PO4(aq) + H2O(l). Is this what I should be using, as it is for the first equivalence point? I'm not sure why acid/base reactions still confuse me... I just don't seem to understand this?


Thank you!

Offline tamim83

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Re: Net ionic equation at 1st equivalence point for NaOH+H3PO4
« Reply #3 on: April 11, 2011, 01:01:46 PM »
Quote
NaOH (aq) + H3PO4(aq)----> NaH2PO4(aq) + H2O(l)

This is the equation for the first equivalence point.  The other equation you had (with the "3NaOH...") is used if you added enough NaOH to remove all of the protons at once, which wouldn't happen in a titration. 

Offline BioMajor

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Re: Net ionic equation at 1st equivalence point for NaOH+H3PO4
« Reply #4 on: April 11, 2011, 01:11:03 PM »
Ok, thanks! I've got it now! :)

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