[student33]

Hi,

I need help with the integration reversible reactions.
I know that for a reversible reaction where A <-> C (forward reaction has a rate constant of k₁ and the reverse reaction has a rate constant of k_-1), the reaction rates are:

d[A]/dt = -k₁[A] + k_-1[C]

and

d[C]/dt = k₁[A] - k_-1[C]

If the initial condition is that [A]_o = [A] + [C]

Then,

d[A]/dt = -k₁[A] + k_-1([A]_o-[A])

I don't get how the integration of this equation will give me:

[A] = [Ao] (k_-1 + k₁e^{-(k₁-k_-1)t})/(k₁ + k_-1)

Any help will be appreciated.

[Jorriss]

http://integral-table.com/

[slavinzing56]

Jorriss  : Wow thanks!