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Topic: Electrolysis  (Read 5401 times)

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Offline Boxxxed

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Electrolysis
« on: April 19, 2011, 08:41:40 PM »
In anticipation to the building of a permanent colony on the moon, scientists are planning to provide a self-sustaining source of oxygen by extracting it out of lunar rocks (which are composed primarily of silica). Thus, both silicon (Si(s)) and oxygen gas (O2(g)) can be produced by the electrolysis of molten silica (SiO2(l)). (Note:  in the liquid state, SiO2 can be considered as a mixture of Si4+ and 2 O2- ions)  Hint:  O2 + 4e- → 2O2-


a.  Write both half-reactions involved in this process, identifying the oxidation and reduction half reactions.  Also, write the balanced equation describing the global reaction.

Is the overall reaction Si4++2O2- ----> Si + O2?

Si4+ is gaining electrons so it's the cathode and O2 is losing it so it's the anode.



b.  How many hours are required to convert 1.00 x 103 kg of SiO2(l) by passing a constant current of 5.00 x 104 A through the melt?


Why are they putting '1.00x103' and '5.00x104', why don't they use a single number? Is there something I am missing here?
« Last Edit: April 19, 2011, 09:17:05 PM by Boxxxed »

Offline rabolisk

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Re: Electrolysis
« Reply #1 on: April 19, 2011, 09:44:02 PM »
You are correct for a. For b, I think they mean 1.00 x 10^3, and 10^4.

Offline Boxxxed

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Re: Electrolysis
« Reply #2 on: April 19, 2011, 09:48:29 PM »
I realized for b) it is scientific notation, the powerpoint didn't use superscripts

Offline Boxxxed

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Re: Electrolysis
« Reply #3 on: April 20, 2011, 12:58:12 PM »
For b) time=charge/current

Moles SiO2 = 1714 x 4 = 16856 moles e-

Charge = Moles e- x 96500

Charge = 6.61x108

time = 6.61x108/ 5x104 = 13232 seconds

Is this right?
« Last Edit: April 20, 2011, 01:58:32 PM by Boxxxed »

Offline Borek

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Re: Electrolysis
« Reply #4 on: April 20, 2011, 01:53:20 PM »
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Boxxxed

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Re: Electrolysis
« Reply #5 on: April 20, 2011, 01:53:33 PM »
c) How many litres of O2(g) will be obtained from this process (at 25 °C and 1 atm)?


Volume = 1714 moles O2 x 0.0821 x 298 / 1 atm = 41934 litres.

d) The O2(g) produced is compressed into a 100 L gas tank.  If the temperature on the moon reaches 107 °C during the day, what will be the pressure inside the gas tank (assume that ideal gas conditions apply here)?

P = nRT/v = 1714(R)(380)/100 = 534 atm

Please let me know if I did these correctly.


Offline Boxxxed

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Re: Electrolysis
« Reply #6 on: April 20, 2011, 01:54:25 PM »

Offline rabolisk

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Re: Electrolysis
« Reply #7 on: April 20, 2011, 01:59:23 PM »
Check your gas constant again.

Offline Boxxxed

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Re: Electrolysis
« Reply #8 on: April 20, 2011, 02:01:29 PM »
Added in the extra decimal place

Offline Borek

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Re: Electrolysis
« Reply #9 on: April 20, 2011, 02:20:04 PM »
Calculated molar mass wrong. Got it

Still wrong.
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Offline Boxxxed

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Re: Electrolysis
« Reply #10 on: April 20, 2011, 02:28:43 PM »
Si = 28.09
O2 = 32

Adds up to 60.09 g/mol

103000g/60.09 = 1714 moles? What is wrong?

Offline rabolisk

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Re: Electrolysis
« Reply #11 on: April 20, 2011, 02:47:51 PM »
103000 grams is 1.00 x 103 kilograms?

Offline Boxxxed

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Re: Electrolysis
« Reply #12 on: April 20, 2011, 02:57:28 PM »
thanks, getting things mixed up again.

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