April 29, 2024, 05:41:48 AM
Forum Rules: Read This Before Posting


Topic: Easier to reduce water in acidic or basic solution?  (Read 3069 times)

0 Members and 1 Guest are viewing this topic.

Offline Boxxxed

  • Full Member
  • ****
  • Posts: 203
  • Mole Snacks: +1/-0
Easier to reduce water in acidic or basic solution?
« on: April 20, 2011, 06:24:51 PM »
2 H2O + 2e- -----> 2OH- + H2

Eo cell = -0.83 v at 25 C

How do I calculate reduction potential at different pH's?

pH = 7

H+ = 1.0x10-7
OH-=1.0x10-7
Q=(2OH)2(H2)
E Cell = -0.83v - 0.0257/2 x In [(2*1.0x10-7)2(1.0x10-7)]

This doesn't give me the right answer. How is this done?


Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27665
  • Mole Snacks: +1801/-410
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Easier to reduce water in acidic or basic solution?
« Reply #1 on: April 20, 2011, 06:47:35 PM »
Why (2OH)2?
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Boxxxed

  • Full Member
  • ****
  • Posts: 203
  • Mole Snacks: +1/-0
Re: Easier to reduce water in acidic or basic solution?
« Reply #2 on: April 20, 2011, 06:58:54 PM »
I don't remember if it's multiplied by its stoichiometric coefficient only in solubility? If it's just OH2 I still get the wrong answer.

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27665
  • Mole Snacks: +1801/-410
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Easier to reduce water in acidic or basic solution?
« Reply #3 on: April 21, 2011, 04:17:33 AM »
It is multiplied by 2 to reflect substance stoichiometry when solving specific type of problems, in general in reaction quotient you have only concentrations and coefficients form only exponents.

You should make use of water ion product.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Sponsored Links