April 23, 2024, 08:48:27 AM
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Topic: Determining how many IR active vibrations a compound has from its point group  (Read 2872 times)

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Offline ampakine

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This is all confusing the hell out of me. I'll use SO2 as an example. It has 3(3) - 6 = 3 degrees of vibrational freedom and it is in the C2v point group. I read that if I count how many bonds are left unchanged by each symmetry operation I get a "reducible representation". It then says that when I find out what irreducible representations the reducible representation is made up of "this result tells us that there are two non-degenerate stretching modes, one of A1 symmetry and one of B2 symmetry."

I'm lost. I read that the A1 (or A2, A3 etc.) label means symmetric with respect to the principle rotation axis (the z axis) and B2 is asymmetric with respect to the principle axis. What does this mean with respect to stretching vibrations? Does this mean that A1 is the label for a symmetric stretch and B2 the label for an asymmetric stretch? If so whats the difference between B1 and B2? In this diagram here:

I'm trying to figure out how the character table relates to the diagram but I'm having serious trouble. How does A1 and B2 represent 2 stretching modes of vibration?

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