Hello,
I have the following question:
If 50.0 mL of a 0.10 M solution of sodium chloride is mixed with 50.0 mL of 0.10 M magnesium chloride, what is the molar concentration of chloride in the resulting solution?
My attempt at solving the problem:
Sodium Chloride is NaCl.
Magnesium Chloride is MgCl2.
M = moles / liters
moles = M * liters
.10 M * (50 x 10^-3 L) = .005 mol sodium chloride
.10 M * (50 x 10^-3 L) = .005 mol magnesium chloride
In 1 mole of NaCl, there is 1/2 moles of Cl. In .005 moles of NaCl, there is .0025 moles of Cl.
In 1 mole of MgCl2, there is 2/3 moles of Cl. In .005 moles of MgCl2, there is .003333 moles of Cl.
Total moles of Cl: .0025 + .003333 = .00583 moles Cl.
M = moles / liters
M = .00583 moles / (100 * 10^-3 L)
M = .0583
That is the answer that I get.
However, the correct answer is 0.15 M.
Where did I make a mistake?