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Topic: calculate the freezing temperature  (Read 2367 times)

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Offline Bjc51192

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calculate the freezing temperature
« on: May 14, 2011, 09:20:25 AM »
Calculate the freezing temperature of a solution made by mixing 55.267 g of cacl2 (mw =110.98) in 250.00g of water
kf =1.86 Cm^-1 ( this is not centimetes)

So what I did was I looked at the problem in a plug and chug mindset, and the formula for freezing point is Tf=kf *m

BUT! CaCl2 is ionic which means we have to get the particals?

the equation will look like this 55.267 * 1mol/110.98 * 3/1

(1.86 C)( 1.49)/.350=7.94

0.00-7.94 = -7.94

My question is do you only get the particals for ionic?

Offline Borek

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Re: calculate the freezing temperature
« Reply #1 on: May 14, 2011, 02:48:23 PM »
My question is do you only get the particals for ionic?

Please elaborate. Do you ask whether ionic substances are the only ones to produce more that one PARTICLE per dissolved molecule? That is, several PARTICLES per molecule?
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Offline Bjc51192

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Re: calculate the freezing temperature
« Reply #2 on: May 15, 2011, 08:31:42 AM »
Sorry, I didnt re read to make sure it was clear. Yes I wanted to know if ionic substances are the only one that contain more than one particle.

Thank you

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