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Topic: Deducing charge of ion  (Read 2185 times)

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Offline xtheunknown0

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Deducing charge of ion
« on: May 27, 2011, 10:57:29 PM »
Hello,

From 4Au(s) + 8CN-(aq) + 2H2O(l) + O2(g) → 4Au(CN)2(aq) + 4OH(aq), how do you work out that the charge on an Au ion is +1?

TIA,
xtheunknow0

Offline enahs

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Re: Deducing charge of ion
« Reply #1 on: May 27, 2011, 11:03:12 PM »
Au(CN)2-
You know it is CN-, so you have 2 negatives but an overall charge of 1 negative, so you Au mus be?

Offline Vidya

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Re: Deducing charge of ion
« Reply #2 on: May 27, 2011, 11:40:12 PM »
Mathematically
sum of all charges is -1 in the complex
let us assume Au is
x+ (-2) = -1
each CN is -1

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