Use Hess's Law to calculate delta H for the reaction: C6H4(OH)2(aq) + H2O2(aq) → C6H4O2(aq) + 2H2O(l)
Given the following data:
C6H4(OH)2(aq) → C6H4O2(aq) + H2(g) deltaH1 = +177.4
H2(g) + O2(g) → H2O2(aq) deltaH2 = -191.2
H2(g) + 1/2O2 → H2O(g) deltaH3 = -241.8
H2O(g) → H2O(l) deltaH4 = -43.8
I know i need to reverse the 2nd equation, and times the 4th equation by 2.
Since the 3rd equation does not include any of the products or reactants of the target equation, do i not need to include it?
Any help would be appreciated!