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Topic: Experiment involvin cu cl  (Read 3182 times)

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g1sk8terz

  • Guest
Experiment involvin cu cl
« on: September 23, 2005, 06:21:44 PM »
ok we did an experiment
in AP chem

Cu(subscript x)Cl(subscript)y + Zn(s) ----> ZnCl(subscript2) + Cu(s)

and
i have found the mass of the copper chloride solution

(beaker + liquid solution mass) - (beaker mass)

so it comes to be 2.02 g of copper chloride in 25.0 mL of solution

and i have calculated the mass of Cu produced....0.230 g

now my problem is...how do i find out how much chlorine is in that solution?




g1sk8terz

  • Guest
Re:Experiment involvin cu cl
« Reply #1 on: September 24, 2005, 09:03:41 AM »
nevermind guys i figured it out.

i was thinkin of the definition of mass % when i came to it

g solution(CuCl) = g solute (cu) + g solvent (cl)

to find g of Cl in Copper Chloride solution

is this right?
« Last Edit: September 24, 2005, 09:09:16 AM by g1sk8terz »

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