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Master_Key

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« on: July 07, 2011, 09:08:28 AM »
Red Lead Pb3O4 :- What is the ratio of Pb +2 and +4 oxidation states in this.

sjb

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« Reply #1 on: July 07, 2011, 10:16:17 AM »
Red Lead Pb3O4 :- What is the ratio of Pb +2 and +4 oxidation states in this.

If it were solely lead (II), what would the formula of the oxide be? What about if it were solely lead (IV)?

Vidya

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« Reply #2 on: July 07, 2011, 11:26:18 AM »
2PbO·PbO2.

Master_Key

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« Reply #3 on: July 08, 2011, 08:46:09 AM »
I meant that I have read that Pb3O4 is a mixture of PbO and PbO2 So what is the ratio of these in the mixture.

Pb3O4 Can carry out the reactions of PbO and PbO2 so i need to find the ratio of +2 and +4 in this.

sjb

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« Reply #4 on: July 08, 2011, 09:29:23 AM »
I meant that I have read that Pb3O4 is a mixture of PbO and PbO2 So what is the ratio of these in the mixture.

Pb3O4 Can carry out the reactions of PbO and PbO2 so i need to find the ratio of +2 and +4 in this.

OK, so you can set up two equations x + y = 3 (for atoms of lead) and x + 2y = 4 (for atoms of oxygen), where x is the amount of lead (IV) oxide and y the amount of lead (II) oxide...

Of course, in this case it's relatively easy by trial and error....

Master_Key

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