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Topic: Balancing using oxidation numbers  (Read 5028 times)

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Viper

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Balancing using oxidation numbers
« on: September 27, 2005, 11:32:56 PM »
hi guys im having a little difficulty trying to understand balancing with oxidation...so heres a sample problem that i really need someone to explain to me

the equation is this:

K2Cr2O7   +   HCl ------->   KCl   +   CrCl3   +   Cl2   +   H2O

and then my teacher gives me this for an answer:

K2Cr2O7   +   6HCl   +   8H2O ------->   2KCl   +   2CrCl3   +   3Cl2   +   7H2O

so i just dont understand how he got there!? Please i would REALLY appreciate it if someone explains it to me becase it is really hard for me to understand.....thnx a lot in advance
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Offline mike

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Re:Balancing using oxidation numbers
« Reply #1 on: September 27, 2005, 11:51:54 PM »
Teacher's answer is wrong.
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Viper

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Re:Balancing using oxidation numbers
« Reply #2 on: September 27, 2005, 11:53:23 PM »
really?...can you tell me what the right answer is please
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Offline mike

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Re:Balancing using oxidation numbers
« Reply #3 on: September 27, 2005, 11:54:57 PM »
K2Cr2O7 + 14HCl ---> 2KCl + 2CrCl3 + 3Cl2 + 7H2O
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There is no science without fancy, and no art without facts.

Viper

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Re:Balancing using oxidation numbers
« Reply #4 on: September 27, 2005, 11:56:52 PM »
Thank you sooo much...just one last question just briefly explain to me how you got that answer i know how to give elements oxidation numbers.
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Offline mike

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Re:Balancing using oxidation numbers
« Reply #5 on: September 27, 2005, 11:58:31 PM »
Just make the number of atoms of each element on the left hand side equal the number of atoms of each element on the right hand side.

It doesn't matter what the oxidation numbers are for this question, it is just math.
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There is no science without fancy, and no art without facts.

Viper

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Re:Balancing using oxidation numbers
« Reply #6 on: September 28, 2005, 12:00:49 AM »
so you dont use oxidation numbers for this one huh...well man cant thank you enough really i owe you one :) see you later
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