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Topic: How to balance this equation?  (Read 18966 times)

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Offline Borek

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Re: How to balance this equation?
« Reply #30 on: March 12, 2010, 05:01:26 PM »
1. You have two atoms of Cr on both sides of the oxidation equation - but you have lost 2 on the RHS of the full equation.

2. No idea why do you think it should be 6 INSTEAD of 3. 3 is wrong - your reduction reaction after being multiplied by 3 will give you 6 atoms of Br (more precisely - six Br- anions) on the RHS.

Seems like you did the same mistake twice.
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Offline Evaldas

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Re: How to balance this equation?
« Reply #31 on: March 13, 2010, 03:25:58 PM »
First, what is RHS?

Offline Borek

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Re: How to balance this equation?
« Reply #32 on: March 13, 2010, 05:25:36 PM »
Right Hand Side, Left Hand Side (of the equation).
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Offline Evaldas

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Re: How to balance this equation?
« Reply #33 on: March 17, 2010, 04:24:04 AM »
There are two P atoms in a product molecule, so it will be easier to write phosphorus part as

2P0 -> 2P+5 + 10e-

(you did the same for oxygen, just the other way around).
First of all, my teacher says you're suppsed to write P0 -> P+5 + 5 e-, in the P + O2 -> P2O5 reaction.

Offline Evaldas

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Re: How to balance this equation?
« Reply #34 on: April 12, 2010, 02:35:20 PM »
I still haven't cracked this topic and I still need help, does anyone know a good web page that explains in a detailed way how to balance the more difficult reactions?

Offline AWK

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Re: How to balance this equation?
« Reply #35 on: September 14, 2011, 02:22:54 AM »
I still haven't cracked this topic and I still need help, does anyone know a good web page that explains in a detailed way how to balance the more difficult reactions?
Try these examples
Pb(N3)2 + Cr(MnO4)2 = Cr2O3 + MnO2 + Pb3O4 + NO
P2I4 + P4 + H2O = PH4I + H3PO4
K4[Fe(CN)6] + Ce(NO3)4 + KOH = K2CO3 + Fe(OH)3 + Ce(OH)3 + KNO3 + H2O
AWK

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