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Topic: Hydrogen peroxdie and water half-equation  (Read 3045 times)

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Offline xtheunknown0

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Hydrogen peroxdie and water half-equation
« on: September 16, 2011, 09:39:34 PM »
Hello,

I'm considering H2O2(aq) + 2H+(aq) + 2e- ::equil:: 2H2O(l) (E0 = 1.77 V). How can water be better at pushing away electrons than water in O2(g) + 4H+(aq) + 4e- ::equil:: 2H2O (E0 = 1.23 V)?

TIA,
xtheunknown0

Offline Hunter2

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Re: Hydrogen peroxdie and water half-equation
« Reply #1 on: September 18, 2011, 09:37:50 AM »
I think you have to compare the corresponded reaction.
Compare Permangante and Peroxide with copper and peroxide in acidic solutions

Offline DevaDevil

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Re: Hydrogen peroxdie and water half-equation
« Reply #2 on: September 19, 2011, 12:01:29 PM »
Hello,

I'm considering H2O2(aq) + 2H+(aq) + 2e- ::equil:: 2H2O(l) (E0 = 1.77 V). How can water be better at pushing away electrons than water in O2(g) + 4H+(aq) + 4e- ::equil:: 2H2O (E0 = 1.23 V)?

TIA,
xtheunknown0

I am confused about your question. Are you asking if water (on a Pt electrode) prefers to oxidize to oxygen or peroxide?


Offline xtheunknown0

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Re: Hydrogen peroxdie and water half-equation
« Reply #3 on: September 25, 2011, 06:06:33 PM »
Yes.

Offline DevaDevil

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Re: Hydrogen peroxdie and water half-equation
« Reply #4 on: September 26, 2011, 09:41:56 AM »
well, considering peroxide decomposes by itself into oxygen and water, what do you think is preferred?

Offline xtheunknown0

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Re: Hydrogen peroxdie and water half-equation
« Reply #5 on: October 02, 2011, 01:10:53 AM »
I don't understand what you're getting at.

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