[gnats50]

Hi, this is really simple, but I can't figure it out. It's driving me crazy.

When 50.00 mL of 1.000x10^-1M Pb(NO3)2 solution was added to 50.00 mL of 1.000x10^-1M NaI solution, 1.021 g of PbI2 was obtained as product.
Calculate the number of moles of Pb(NO3)2 used.


Thank You for your help. I really want to know how to get to the answer and not just the answer.

[Borek]

Write down reaction equation.

[Mitch]

First always start by writing the balanced chemical equation.

[Borek]

First always start by writing the balanced chemical equation.

I was first

[gnats50]

Pb(NO3)2(aq)   +   2 NaI(aq)   ----->  2 NaNO3(aq)  +   PbI2(ppt)

[Mitch]

You have grams PbI2 convert it to moles PbI2 relate it to moles of Pb(NO3)2 and convert that into grams of Pb(NO3)2 and you're all done.