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Topic: Anthranilacid (= o-Amino-benzoic-acid) and make Diphenyl-2,2'-Dicarboxylic acid  (Read 4745 times)

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Offline FeLiXe

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Hi,

Could someone help me with a reaction I am supposed to do in my lab. I don't really get what happens. What I am doing is: Start with Anthranilacid (= o-Amino-benzoic-acid) and make Diphenyl-2,2'-Dicarboxylic acid.

It goes like this: 1. Make the diazonium salt with nitrous acid.
2. in a second flask I let Copper(II)sulfate react with hydroxyl-amine (1:1). what happens then? do I get Copper and H-N=O? Any reaction seems totally weird to me.
3. Combine the two flasks. Somehow the diazogroup leaves  and I get my product.

The two Anthranilic acids are condensed (eliminating the two NH2 groups).

I would appreciate any ideas or hints on that reaction.

Thanks
« Last Edit: October 27, 2005, 02:10:51 AM by Mitch »
Math and alcohol don't mix, so... please, don't drink and derive!

Offline movies

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Re:Diazotisation
« Reply #1 on: October 09, 2005, 03:17:10 PM »
Check out the Sandmeyer Reaction and it's related reactions.

Offline FeLiXe

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Re:Diazotisation
« Reply #2 on: October 09, 2005, 04:19:24 PM »
ok, thanks

Sandmeyer, Gomberg those are kind of like what I am supposed to do. I still have no idea though what hydroxyl-amine could be useful for. But it's no big deal. I'll have to ask the assistant and hope that he still gives me a nice grade even though I couldn't figure the reaction out.
Math and alcohol don't mix, so... please, don't drink and derive!

Offline FeLiXe

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Re:Diazotisation
« Reply #3 on: October 09, 2005, 04:33:03 PM »
alright, according to the sandmeyer reaction it makes sense, just needed a little hint into the right direction.

The hydroxylamine is just the reducing agent, that I use to get copper(I). That helps me make radicals out of the diazonium-salt. And the radicals combine.
Math and alcohol don't mix, so... please, don't drink and derive!

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