April 20, 2024, 06:44:11 AM
Forum Rules: Read This Before Posting


Topic: Combined gas law + Avogadro's law  (Read 3220 times)

0 Members and 1 Guest are viewing this topic.

Offline Foobarz

  • Regular Member
  • ***
  • Posts: 73
  • Mole Snacks: +0/-2
Combined gas law + Avogadro's law
« on: October 28, 2011, 10:55:21 PM »
Okay so the combined gas law is (P1V1)/T1 = (P2V2)/T2. And Avogadro's law is n1/V1 = n2/V2. My question is can these two be combined to show that Pressure is also directly proportional to number of moles and that temperature is indirectly proportional to number of moles, shown by n1/P1 = n2/P2 and n1*T1 = n2*T2 ?

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27652
  • Mole Snacks: +1800/-410
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Combined gas law + Avogadro's law
« Reply #1 on: October 29, 2011, 05:31:49 AM »
Technically there is nothing wrong with such approach. You just have to remember these equations will hold only with assumption that all other parameters are kept constant.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline fledarmus

  • Chemist
  • Sr. Member
  • *
  • Posts: 1675
  • Mole Snacks: +203/-28
Re: Combined gas law + Avogadro's law
« Reply #2 on: October 29, 2011, 04:24:48 PM »
yes - once you put everything together in the ideal gas law, you can hold anything you want constant and find out how anything else will change.

P1V1 = P2V2
n1T1    n2T2

Offline Foobarz

  • Regular Member
  • ***
  • Posts: 73
  • Mole Snacks: +0/-2
Re: Combined gas law + Avogadro's law
« Reply #3 on: October 29, 2011, 06:05:19 PM »
So number of moles is inversely proportional temperature? Could someone explain that to me?

Offline juanrga

  • Full Member
  • ****
  • Posts: 231
  • Mole Snacks: +16/-11
    • juanrga - sharing unified knowledge in pure and applied sciences
Re: Combined gas law + Avogadro's law
« Reply #4 on: October 30, 2011, 11:23:58 AM »
So number of moles is inversely proportional temperature? Could someone explain that to me?

If pressure and volume are the same you get $$ n_1 T_1 = n_2 T_2 /$$

This is correct. If you increase the number of molecules $$ N /$$, you are dividing the energy between more particles and, thus, the average energy

$$ \langle E \rangle = \frac{E}{N} /$$

And temperature is related to average energy

$$ T \prop \langle E \rangle /$$
Sharing unified knowledge in pure and applied sciences

Offline Foobarz

  • Regular Member
  • ***
  • Posts: 73
  • Mole Snacks: +0/-2
Re: Combined gas law + Avogadro's law
« Reply #5 on: October 30, 2011, 04:19:50 PM »
But that means if you remove moles of a gas, the temperature goes up? How does that make sense?

Offline Foobarz

  • Regular Member
  • ***
  • Posts: 73
  • Mole Snacks: +0/-2
Re: Combined gas law + Avogadro's law
« Reply #6 on: October 30, 2011, 04:23:47 PM »
Oh wait, never mind, I forgot that P and V have to be constant. So the lesser number of moles have to move faster (higher temperature) to maintain the same volume and pressure as the original number of moles.

Thank you all for your explanations!
« Last Edit: October 30, 2011, 04:52:55 PM by Foobarz »

Sponsored Links