Hello, all. I have a question regarding the dissociation of an element
We recently did a lab experiment where we measured the varying conductivity of water in which we initially added a dilute solution of Ba(OH)2
and then added increasing amounts of H2SO4
and watched as the conductivity dropped, hit the equivalence point and then increased.
The relationship of the volume of H2SO4
to conductivity was linear, which I guess makes sense, since presumably the electrons are getting paired ("used up") at the same ratio every time, and conductivity is just
is resitivity. (?)
But my real question is this. I know this reaction is taking place because the Barium ions dissociate once it is the barium hydroxide is dissolved in water. And I know that the barium then bonds to the sulfate in the sulfiric acid. I'm just curious as to why I should know that the Barium would dissociate if someone hadn't told me.
I'd venture this has something to do with the the fact that barium's 6th s-shell is full (has two electrons) thus the Barium is inclined to give away electrons. But why does it ditch the hydroxide as soon as it hits the water? Are some of the H
molecules and the O
moleulces forming up to make water together and leaving a few oxygen's floating around as unbonded ions?
Edit: added more descriptive title