Hi there, this question is for high school chemistry grade 12. The unit we're working on now is studying bonding and structure properties. We conducted various experiments and in this particular experiment I mixed:
- iodine with water, hexane, and ethanol
- graphite with water, hexane, and ethanol
- Calcium Chloride (CaCl
2) with water, hexane, and ethanol
and we had to test the conductivity of each solution (after mixing). The results yielded are:
+ Water Hexane Ethanol
Iodine 103 mV 11 mV 0.3 mV
Graphite 109 mV 83 mV 0.4 mV
CaCl2 207 mV 84 mV 2 mV
(mV = millivolts)
I tried to come up with a good explanation for any of the above but I keep getting stuck.
I know that iodine and water don't mix, and that water is polar and iodine isn't, so when the current is run through the water, the I
2 molecules would hinder the current and therefore lower the voltage? Is that the correct way to approach this?
Again, with the graphite, that doesn't mix with the water, and it is "bigger" than the iodine, so why would it yield a higher voltage than iodine+water?
My final question for now is, how come ethanol has such lower conductivity than hexane even though ethanol is partially polar and hexane is completely non-polar?
This whole thing is giving me a headache
Any help would be appreciated!
- Omar