Yes, ΔS is meant to be positive, you can just work it out by 4.0345*8.314 = 33.54 J K^{-1} mol^{-1}

Its just that the equation for my first graph is ΔG = ΔH - TΔS the slope should be -ΔS. When I plotted it, the slope came out as -33.54 so this is equal to -ΔS hence ΔS is 33.54, same as calculated above.