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Topic: chemical equilibrium  (Read 2643 times)

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Offline rayyau35

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chemical equilibrium
« on: November 20, 2011, 05:07:58 AM »
2.00L flask was filled with 2.00 moles of SO2 gas and 2.00 moles of NO2 gas and heated.After equilibrium was reached at 400 DEGREE C,it was founded that 1.30 moles of NO gas was present.The reaction occurring is represented by the following equation.
SO2+ NO2 ----->SO3 +NO

1.Calculate the value of the equilibrium constant.K for this reaction.
2.Calculate the value of the equilibrium constant K" at 400C,for the reaction shown below:
  SO3+NO------->SO2+NO2

Offline sjb

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Re: chemical equilibrium
« Reply #1 on: November 20, 2011, 06:52:51 AM »
2.00L flask was filled with 2.00 moles of SO2 gas and 2.00 moles of NO2 gas and heated.After equilibrium was reached at 400°C,it was founded that 1.30 moles of NO gas was present.The reaction occurring is represented by the following equation.
SO2+ NO2  :rarrow: SO3 +NO

1.Calculate the value of the equilibrium constant.K for this reaction.
2.Calculate the value of the equilibrium constant K" at 400°C,for the reaction shown below:
  SO3+NO------->SO2+NO2

If there are now 1.30 mol of NO, how much SO3 is there? If you started with 2.00 mol of SO2, how much is there left?

Offline Vidya

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Re: chemical equilibrium
« Reply #2 on: November 20, 2011, 07:46:35 PM »
you know the moles of NO reacted so you calculate the equilibrium moles of each of the reactant from the balanced equation.Divide these moles with volume of the container to get the concentrations of each of the substance(reactant and products) at the equilibrium.Now you can use formula the calculations of K(equilibrium constant).

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