Here's the problem:

.50000g 1,3-dimethylcyclohexane reacts with chlorine to give mono-chlorinated products. All the dimethylcyclohexane is used up. Relative rates of reactivity for tertiary, secondary and primary hydrogens under free radical chlorination conditions are 5.0, 3.6 and 1.0 respectively. Ignoring stereoisomers calculate the number of grams of each unique mono-chlorinated product. Show work.

So here's my take:6 total primary Hydrogens, 8 secondary and 2 tertiary. With the rates given that means the ratio is primary: 1*6=6, secondary: 3.6*8=28.8 tertiary: 5*2=10. As far as determining amount of product, percentage-wise that gives me primary: 6/44.8= 13.4% secondary= 28.8/44.8=64.3% tertiary: 10/44.8=22.3%. I have .5/114.23= 0.0043771 moles of dimethylhexane so I'm thinking I need to add that many moles of chlorine to the .5g of dimethylcyclohexane to get the total weight from which I will take my percentages. With my percentages of that total weight I should be correct.....right?