BH3 <-- Boron trihydride
If you are to draw a Lewis structure, you would see that just a single bond is needed b/ween each B-H bond. Is Boron coordinate covalent bonding in this situation?
Also, its electron configuration before bonding is 1s^2 2s^2 2p^1
After bonding with those 3 Hydrogens, is its valence configuration going to be:
1s^2 2s^0 2p^0 OR
Does it hybridize and we get:
[e-, ][e-, ][e-, ] <--- sp^2 [e-, ] <--- p
What I am not understanding is how does Boron's valence configuration change before bonding versus after bonding?