A 29.85 g aluminum block is warmed to 65.91 °C and plugged into an insulated beaker containing 97.61 g water initially at 16.73 °C. The aluminum and the water are allowed to come to thermal equilibrium. Assuming that no heat is lost, what is the final temperature of the water and aluminum?
I'm pretty sure that what I need to do is, q = -q, as in q Al cooling = - water heating, but usually when i have these problems I'm at least given a specific heat, and my professor will usually give us that constant if we need to use it, so is there something that I'm missing here? I'm not really sure how to start this without more information given. Thanks