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Topic: help needed again. I don't understand these sugars at all  (Read 3224 times)

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Offline chunli

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help needed again. I don't understand these sugars at all
« on: December 18, 2011, 09:18:35 AM »
Aldose A is optically active, but treatment with NaBH4 gives alditol B,
which is optically inactive.
Aldose A undergoes Ruff degradation to give Compound C. When
Compound C is treated with NaBH4
, optically inactive alditol D is
formed. However, when C undergoes Ruff degradation, optically active
D-glyceraldehyde is obtained. Give the structures and names of sugars
A–D :(

Offline sjb

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Re: help needed again. I don't understand these sugars at all
« Reply #1 on: December 18, 2011, 09:21:21 AM »
Aldose A is optically active, but treatment with NaBH4 gives alditol B,
which is optically inactive.
Aldose A undergoes Ruff degradation to give Compound C. When
Compound C is treated with NaBH4
, optically inactive alditol D is
formed. However, when C undergoes Ruff degradation, optically active
D-glyceraldehyde is obtained. Give the structures and names of sugars
A–D :(

What does Ruff degradation do to a compound, consider a generic structure, perhaps? What then could C be? If on reduction you get an optically inactive compound, what does that suggest?

Offline Dan

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Re: help needed again. I don't understand these sugars at all
« Reply #2 on: December 18, 2011, 06:35:29 PM »
For this question, I would work backwards from glyceraldehyde. There are only two sugars that will produce D-glyceraldehyde by Ruff degradation. Apply the chirality information to determine which one it is, this gives you C/D. Then repeat this exercise on C to find A/B.
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