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Topic: Deriving an equation for heat of vaporization of Freon-22  (Read 3485 times)

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Offline bearcaller

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Deriving an equation for heat of vaporization of Freon-22
« on: December 06, 2011, 01:23:15 AM »
i have to derive the following equation for heat of vaporization DeltaH=R(4270-7.96T)
I am given DeltaH=15.65kJ/mol, Po =10.86 atm, Cp(l)=121.2J/K, Cp(g)=55.0J/K,
so far all i have gotten to convert the equation into the following: DeltaH = R(4270-(DeltaCp*T)/R)
i am pretty lost if i could just get a little guidance thatd be great
thanks

Offline wolfzhchk

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Re: Deriving an equation for heat of vaporization of Freon-22
« Reply #1 on: December 31, 2011, 10:08:14 AM »
i have to derive the following equation for heat of vaporization DeltaH=R(4270-7.96T)
I am given DeltaH=15.65kJ/mol, Po =10.86 atm, Cp(l)=121.2J/K, Cp(g)=55.0J/K,
so far all i have gotten to convert the equation into the following: DeltaH = R(4270-(DeltaCp*T)/R)
i am pretty lost if i could just get a little guidance thatd be great
thanks

What do you mean that [;\Delta H = R\left( {4270 - 7.96T} \right);] ? Phase transfer?

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