March 29, 2024, 02:54:16 AM
Forum Rules: Read This Before Posting


Topic: determination of F- in toothpaste  (Read 5663 times)

0 Members and 1 Guest are viewing this topic.

Offline dnbwise

  • Regular Member
  • ***
  • Posts: 31
  • Mole Snacks: +1/-5
  • I'm a mole!
determination of F- in toothpaste
« on: October 30, 2005, 10:00:56 PM »
I added 10 mL of toothpaste into a beaker and used a F- detecting electrode to take measurments of potential (mV). I used standards to construct a calibration curve and calculated [F-] of toothpaste by the calibration curve. I have the fluoride concentration in ppm ([F-] = 1.919 ppm) now I need to find grams F-. (1ppm = 1ug/mL)

(1.919 ug/mL)(10^-6g/ug)(10ml) = 1.919*10^-5 g

does this look like the correct calculation for determining F- grams from the [F-]?

Offline sdekivit

  • Chemist
  • Full Member
  • *
  • Posts: 403
  • Mole Snacks: +32/-3
  • Gender: Male
  • B.Sc Biomedical Sciences, Utrecht University
Re:determination of F- in toothpaste
« Reply #1 on: October 31, 2005, 10:20:30 AM »
looks correct.

skyaintsnow

  • Guest
Re:determination of F- in toothpaste
« Reply #2 on: November 15, 2005, 01:24:20 PM »
it's right.

An easier way to convert the unit is to use the equivalent unit of ppm, mg/liter. You don't need to worry about the 106 part then.

Sponsored Links