I was thinking along the lines of using an iodide to extract the lead and then a hydroxide to precipitate the nickel.
That's not really a good idea....lead(II)iodide is an insoluble (in water ) precipitate, but it is soluble in excess I
- as a tetraiodo complex....
Pb
2+ + 2 I
- ----> PbI
2(s)PbI
2(s) + 2 I
- ----> PbI
42-Try to precipitate the nickel as Ni(OH)
2 with NaOH (lead hydroxide is soluble in excess NaOH as a tetrahydroxoplumbate(II)- complex). After separation (by filtration) of the nickel hydroxide precipitate the Pb
2+(aq) with potassium chromate.
Roast the nickel hydorxide:
Ni(OH)
2 ------> NiO + H
2O
Dissolve in sulfuric acid:
NiO + H
2SO
4 ---> NiSO
4 + H
2O
Nickel sulfate forms.
I'll post more later, I'm in a rush!