@fledarmus

I wrote

outside the refrigerator is P_{1} = 101325 Pa

inside the refrigerator is P_{2 }= 94412 Pa

The difference between inside and outside pressure = 6913 Pa

later

1 Pa = 1 N/m^{2} where N is newton and m is meter

Since the door is 1m^{2} the force to open = 6913 N

Alternatively I could have said

outside the refrigerator is P

_{1} = 101325 Pa

inside the refrigerator is P

_{2 }= 94412 Pa

and

1 Pa = 1 N/m

^{2} where N is newton and m is meter

Since the door is 1m

^{2}the force outside the refrigerator is 101325 N

the force inside the refrigerator is 94412 N

The difference between these forces is

6913 Nwhich is the force necessary to open the door

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@fledarmus

Is the second way a better way of presenting the results,since the final answer in both is the same?

Or

is my physics rusty

@Wastrel

For me it would have been useful to couch what the force would be like by stating in lifting of grams against gravity. I do not have a since in my mind about newtons.

Example

The newtons are for opening the door feel the same as lifting a

gram weight against gravity.

do you want to fill in the grams?