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Common ion, complex ion, molar solubility problem.
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Topic: Common ion, complex ion, molar solubility problem. (Read 6518 times)
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zainsiddiqui14
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Common ion, complex ion, molar solubility problem.
«
on:
February 18, 2012, 05:27:48 PM »
The copper(I) ion forms a chloride salt that has Ksp = 1.2 * 10^-6. Copper(I) also forms a complex ion with Cl-.
Cu+(aq) + 2 Cl-(aq) yields CuCl2-(aq) K = 8.7 * 10^4
(a) Calculate the solubility of copper(I) chloride in pure water. (Ignore CuCl2- formation for part a.)
I got this one, it's .0011 molar.
(b) Calculate the solubility of copper(I) chloride in 0.36 M NaCl.
Where do I start?
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Borek
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Re: Common ion, complex ion, molar solubility problem.
«
Reply #1 on:
February 18, 2012, 06:48:01 PM »
Concentration of Cl
-
is given, just put it into Ksp formula. What is known, what is unknown?
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ChemBuddy
chemical calculators - stoichiometry, pH, concentration, buffer preparation,
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zainsiddiqui14
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Re: Common ion, complex ion, molar solubility problem.
«
Reply #2 on:
February 18, 2012, 10:58:23 PM »
That's what I thought initially, too.
Ksp = [Cu+][.37], right?
No, actually.
Because Cu+ and Cl- then make a complex and ion, that further affects the solubility, which is where I'm confused.
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Borek
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Re: Common ion, complex ion, molar solubility problem.
«
Reply #3 on:
February 19, 2012, 05:23:45 AM »
OK. Assume concentration of Cl
-
doesn't change. You will get two equations in two unknowns - free copper(I) and copper(I) complex. Try to solve.
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ChemBuddy
chemical calculators - stoichiometry, pH, concentration, buffer preparation,
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zainsiddiqui14
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Re: Common ion, complex ion, molar solubility problem.
«
Reply #4 on:
February 19, 2012, 10:07:53 AM »
Oh, haha, I overlooked something really quite simple. Only aqueous and gaseous species appear in the K expression, and I erroneously put CuCl(s) in the expression and kept thinking, "there are too many unknowns!". In reality, if you add the two equations together and multiply K values (Hess's law), you get quite simply:
.1044=[CuCl2-]/[Cl-]
.1044 =
/[.36-x]
x=.034 M
Thanks for the pointers!
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Common ion, complex ion, molar solubility problem.