Pyridine: what you have drawn, is a correct structure. It has a LP of electrons that cannot conjugate into the pi system because it's vacant orbital lies perpendicular to the pi plane. Hence there will only be one pi electron and 2 sigma.
That compound with sulphur replacing the nitrogen (which I think you are stating), does not exist and will never exist. Why? because sulphur does not form 3 bonds, its either forms 2 bonds (filling up its vacant p orbitals) or it spd hybridises to form 6 bonds. Nothing else in between.
There is a compound called thiophene which I think you mean. This is aromatic, if you look at the plane the electrons lie in in sulphur and then in the rest of the compound you should be able to work out how many pi electrons are donated from sulphur.