March 28, 2024, 09:47:47 PM
Forum Rules: Read This Before Posting


Topic: Calculating pH from deltaG° and Ion Concentrations  (Read 5966 times)

0 Members and 1 Guest are viewing this topic.

Offline RNix25

  • Very New Member
  • *
  • Posts: 2
  • Mole Snacks: +1/-0
Calculating pH from deltaG° and Ion Concentrations
« on: April 11, 2012, 05:01:49 PM »
I've been working on this one for a few days, and I just cant seem to get the right answer.

Consider the reaction I2(s) --> I- (aq) +  IO3- (aq)
Balanced= 3I2 + 6OH-  -->  5I- + IO3- + 3H2O

deltaG°= -153.8 kJ/mol

The question: What pH is required for the reaction to be at equilibrium at 298 K when [I-]= 0.5 M and [IO3-]= 0.5 M

I know the answer is 9.21, but I just can't figure out how to get there. I started by finding Keq, which is 9.113 * 10^26, but I'm stumped from there. I would be extremely appreciative for a walkthrough of to the final answer.

Offline JustinCh3m

  • Regular Member
  • ***
  • Posts: 95
  • Mole Snacks: +12/-8
    • CollegeChemistryNotes
Re: Calculating pH from deltaG° and Ion Concentrations
« Reply #1 on: April 11, 2012, 05:21:39 PM »
set up the equilibrium expression.  the only unknown will be the denominator, [OH-].  Solve for [OH-] and you should be able to figure it out from there.

PS - I'm assuming your value for Keq is correct.

Offline RNix25

  • Very New Member
  • *
  • Posts: 2
  • Mole Snacks: +1/-0
Re: Calculating pH from deltaG° and Ion Concentrations
« Reply #2 on: April 12, 2012, 04:32:20 PM »
Thanks for responding. I had my one of my concentrations off, so I kept getting the wrong pH. Still, the quick response is appreciated.

Sponsored Links