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Topic: d-d transition, solvent as ligand  (Read 8299 times)

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Offline Winga

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d-d transition, solvent as ligand
« on: November 14, 2005, 01:45:08 PM »
e.g. a square planar complex

For dxz,dyz ---> dz2 transition, if there is no electron in dz2 orbital of metal centre, when a solvent molecule acts as a ligand to attach the metal centre at z-axis, then, the dz2 is stablized or destabilized?

skyaintsnow

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Re:d-d transition, solvent as ligand
« Reply #1 on: November 15, 2005, 01:35:01 PM »
I'd put destablized. dz2, its spatial arrangement causes repulsion with ligand electrons

Hey wait, square planar, how come d2 is involved?

Offline Winga

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Re:d-d transition, solvent as ligand
« Reply #2 on: November 15, 2005, 02:50:49 PM »
If there is no electron in dz2, how comes the electron-electron repulsion with ligand's lone pair.

You mean the empty dz2 orbital repels ligand's lone pair?

skyaintsnow

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Re:d-d transition, solvent as ligand
« Reply #3 on: November 15, 2005, 03:14:30 PM »
sorry, I was talking about octahedral. I reconsidered it, maybe only dx2-y2 has repulsion. After splitting all other orbitals are stablized.

Offline Winga

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Re:d-d transition, solvent as ligand
« Reply #4 on: November 16, 2005, 04:55:42 AM »
I just wonder that there is destabilization of filled dz2 orbital when a ligand attaches to the metal centre at z-axis, while there is stabilization of unfilled dz2 orbital when a ligand attaches to the metal centre at z-axis.

Offline Winga

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Re:d-d transition, solvent as ligand
« Reply #5 on: December 02, 2005, 06:40:03 AM »
Can anyone help?

AgG

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Re:d-d transition, solvent as ligand
« Reply #6 on: December 02, 2005, 01:19:13 PM »
the crystal field arises as a result of the inherant geometry of the system whether or not the orbitals are filled.  The crystal field splitting diagram for a five coordinate square pyramidal complex looks similar to square coordinate complexes but the energy of the z2 orbital is higher than it is in the square planar complex as a result of interaction with the new ligand.

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