[Gobo]

3Cu(s) + 2MnO4- (aq) + 8H+(aq) ---> 3 Cu2+(aq) + 2 MnO2(s) + 4H2O(l)
I was trying to write a cell diagram for this, but then I realized that there is also a (l) form, and stoichiometric coefficients are involved, so I got quite confused.

My Try:
Cu(s) | Cu2+(aq) || MnO42-(aq) , 8H+(aq) | MnO2(s) | H2O(l)

The equation for the MnO42- reduction is:
MnO4-(aq) + 4H+(aq) + 3e- --> MnO2(s) + 2H2O(l)
(I had to balance the e- for the equation of the question so that is why I ended up with 8H+ and not 4H+).

In short, my questions are:
a) is my try correct?
b) do we ever include stoichiometric coefficients in cell diagrams?



The oxidation equation, by the way, is:
Cu(s) ---> Cu2+(aq) + 2e-

NOTE: I already balanced it.

[JustinCh3m]

your redox equation has it's atoms and charges balanced, and your line notation looks correct. 

usually coefficients are used in line notation, but leaving them out is not usually considered "incorrect" per se.

[Borek]

MnO4- (aq)

MnO42-(aq)

MnO42-

MnO4-(aq)

So, which one it really is?