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Topic: Standard Gibbs Energy from standard reduction potentials  (Read 4782 times)

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Offline BreakingBad20

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Calculate the standard Gibbs energy and the equilibrium constant of the following reaction at 25°C:      
         Sn(s) + 2AgCl(s)  :rarrow:  SnCl2(aq) + 2Ag(s)       

Given the standard reduction potentials of AgCl/Ag as being +0.22V and that of Sn2+/Sn as being -0.14V.

Equilibrium Equation: Kc = ([SnCl2][Ag]^2)/([Sn][AgCl]^2)

Half Equations:
Right: Sn2+ + 2e-  :rarrow: Sn
Left: AgCl  :rarrow: Ag + Cl-

E° = E°(Right) - E°(Left)
E° = (-0.14) - (+0.22)
E° = -0.36V

I have 2 questions:
Do I use the equation ΔG°cell = −nFE°cel for standard Gibbs energy?

How do I answer this question further?

Offline BreakingBad20

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Re: Standard Gibbs Energy from standard reduction potentials
« Reply #1 on: May 10, 2012, 08:07:42 AM »
Actually I've solved it ;D

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