I have a following problem:
In unaerobic enviroment, there is Manganese dioxide and hydrogen sulfide.
SO42- + 10 H+ + 2 e- <-> H2S + 4 H2O EH0 = + 0,31 V
MnO2(s) + 4 H+ + 2 e- <-> Mn2+ + 2 H2O EH0= + 1,29 V
I'm asked to do pe vs. pH diagram. Can anyone tell me how to do this?