[shalikadm]

We have taught that there must be a directly bound H atom to the C atom which is bound to the benzene ring to oxidize alkylbezene(benzene ring-CH₃) with strong oxidants (H⁺/KHmO₄ heat )unlike non-alkylebenzene(benzene ring-C≡CH)

1.Do we need such thing (a directly bound H atom to the C atom which is bound to the benzene ring) to oxidize alkylbezene with alkaline KMnO₄ to get benzoate ion ?

2.It says that we can oxidize toluene with soft oxidants (MnO₂) to get benzaldehyde.Can we get benzaldehyde from any  alkyl or non-alkyl benzene with soft oxidants ?

[discodermolide]

We have taught that there must be a directly bound H atom to the C atom which is bound to the benzene ring to oxidize alkylbezene(benzene ring-CH₃) with strong oxidants (H⁺/KHmO₄ heat )unlike non-alkylebenzene(benzene ring-C≡CH)

1.Do we need such thing (a directly bound H atom to the C atom which is bound to the benzene ring) to oxidize alkylbezene with alkaline KMnO₄ to get benzoate ion ?

2.It says that we can oxidize toluene with soft oxidants (MnO₂) to get benzaldehyde.Can we get benzaldehyde from any  alkyl or non-alkyl benzene with soft oxidants ?

1. Yes you require a CH species on the carbon attached to the aromatic ring.
2. The benzylic carbon atom will be the one which is oxidized, all other things being equal. MnO₂ should do this and stop without further oxidation to the acid.

[shalikadm]

thanks for the quick reply

[canadapolar]

Thank you, this was helpful for me, too.