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Topic: Reaction mechanism of hydrotris(1-pyrazoyl)borate formation?  (Read 1696 times)

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Offline janapix

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On reacting sodium borohydride with pyrazole, I get a scorpionate ligand.
I'm not very sure how the reaction proceeds though because I thought borohydrides were just
good for transferring protons. Here, the boron atom links directly to nitrogen.


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Offline orgopete

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Re: Reaction mechanism of hydrotris(1-pyrazoyl)borate formation?
« Reply #1 on: June 04, 2012, 05:31:36 PM »
If you draw NaBH4, what are the formal charges?
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Offline janapix

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Re: Reaction mechanism of hydrotris(1-pyrazoyl)borate formation?
« Reply #2 on: June 04, 2012, 06:45:16 PM »
One of the hydrogens on NaBH4 is a hydride anion... but I've two
rubbishy options for a mechanism from this point:

1. hydride donation to -NH- giving -NH2-, where nitrogen temporarily contains 10 electrons
and donates a pair to boron, giving both N and B 8 valence electrons.

2. -NH- nitrogen begins by donating a lone pair to BH4, which then loses its hydride anion. The H- then proceeds to act as a base, removing H from -NH(BH3)-

Do these make sense? I get the feeling they're both completely wrong.

note: -NH- refers to the -NH- of pyrazole, as opposed to the -N=

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