April 29, 2024, 05:05:04 AM
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Topic: What is the vapor pressure inside a pressure cooker when the temperature is 112C  (Read 4488 times)

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Offline Calicum

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I know the formula is ln(p1/p2) = ΔHvap/R (1/T2 - 1/T1) but I keep getting the answer wrong.

So far I got:

p1=1
p2=???
T1=373K
T2=385K
ΔHvap=40.65
R=0.0082

Offline sjb

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I know the formula is ln(p1/p2) = ΔHvap/R (1/T2 - 1/T1) but I keep getting the answer wrong.

So far I got:

p1=1
p2=???
T1=373K
T2=385K
ΔHvap=40.65
R=0.0082

What are your units for R?

Offline Calicum

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I know the formula is ln(p1/p2) = ΔHvap/R (1/T2 - 1/T1) but I keep getting the answer wrong.

So far I got:

p1=1
p2=???
T1=373K
T2=385K
ΔHvap=40.65
R=0.0082

ΔHvap=40.65 KJ/mol
R=0.0082 KJ/mol K

What are your units for R?

Offline Calicum

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Nvm I got my answer.  ;D

Offline JonG

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 R should equal 8.314 J/K mol

Offline Calicum

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R should equal 8.314 J/K mol


 ??? ???

Since my ΔHvap is in KJ/mol it would make sense to change R into KJ/mol too. I do not understand what you mean.

Offline Borek

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R should equal 8.314 J/K mol


 ??? ???

Since my ΔHvap is in KJ/mol it would make sense to change R into KJ/mol too. I do not understand what you mean.

If you used R equal to 0.082 your units were  L atm K-1 mol-1.
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Offline Calicum

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R should equal 8.314 J/K mol


 ??? ???

Since my ΔHvap is in KJ/mol it would make sense to change R into KJ/mol too. I do not understand what you mean.

If you used R equal to 0.082 your units were  L atm K-1 mol-1.

Bah in my first post I wrote 0.0082 and not 0.0083.

My second post corrected this hence the 0.0083KJ/mol which is also equal to 8.314 J/K mol too. Just a little misunderstanding

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